Gravitational Field Difference on the Human Body while approaching a Black Hole Newtons Law of Gravitation: Where: F is the gravitational force G is the gravitational constant m1 is the mass of object 1 m2 is the mass of object 2 r is the radius between the two objects The force (F) is directly proportional to the product of the 2 objects masses, and inversely proportional to the square of the distance between them. We will use the super massive black hole at the center of our Milky Way galaxy, which has been calculated to have a mass of 4.1 million solar masses, or 8.15457x1036 kg. This value will be our m1. For m2, we will use an average person of 150 lbs, or 68.03886 kg. m1= 8.15457x1036 kg m2= 68.03886 kg G= 6.673x10-11 N∙m2/kg2 Next we will use an average height of human being, say 5 ft 7 inches, which is 1.7018 m. We will take 2 measurements, to show that the gravitational field difference is different at a person’s head, or their feet. We will first take a standard distance away from black hole, say 1 km. Now if we measure from the feet up to the head, the feet will be at 0 m, and the head would be at 1.7018. This means that our first distance would be 1000 m, while or second distance would be 1001.7018 m. Let’s analyze the first equation which would be the force at the feet. For the second calculation, we will use the same equation, except use the second distance we found. This results in the following: This may not look like a big difference at all, but the gravitational force at your feet is actually 1.25644x1020 N, that’s 125,644,000,000,000,000,000 N bigger than at your head!