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Today's Agenda .f 1/7/11
Recall – Predicting and classifying chemical
reactions.
 Get your comp books out before the bell rings

Correct problems 3 + 4 from the Stoichiomtry
worksheet in your notebook

Homework: problems 5 + 6 on Stoichiomtry
worksheet in your notebooks.

4/1/2015
http://teachers.yourhomework.com/blowe/
1
Quiz Reminder
Quiz next Tuesday 1/11/11
4/1/2015
Recall
Balance the following Chemical Reactions:
1.C2H2 + O2  CO2 + H2O
2.Fe(OH)2 + H2O2  Fe(OH)3
3.FeS2 + Cl2  FeCl3 +S2Cl2
• 2C2H2 + 5O2  4CO2 + 2H2O
• 2Fe(OH)2 + H2O2  2Fe(OH)3
• 2FeS2 + 5Cl2  2FeCl3 +2S2Cl2
4/1/2015
http://teachers.yourhomework.com/blowe/
3
Recall 2
State the type of Reaction, Predict the products
and Balance the following Chemical Reactions:
1.Aluminum + Sulfur 
2.Aluminum + Oxygen 
3.Iron (III) oxide 
Al + S 
Al2S3
Synthesis
Al + O2  Al2O3
Combustion and Synthesis
Fe2O3  Fe + O2
Decomposition
12/13/10
http://teachers.yourhomework.com/blowe/
4
Problem 3
Magnesium chloride can composed into
magnesium and chlorine.
Magnesium chloride is
Mg2+ and Cl1-
MgCl2
Why is it 2 again?
Because it’s a gas
Magnesium is Mg
Chlorine is Cl2
MgCl2  Mg + Cl2
4/1/2015
Is this equation balanced?
YES!
Problem 3 on Stoichiomtry WS
MgCl2  Mg + Cl2
MgCl2
Moles
(mol)
1.5 x
1
1
Mass
(g)
Molar 
Mass
(g/mpl)
4/1/2015
 1.5
1.5 x 95.21
= 142.82
36.5 g of Mg
Mg
36 .5
24 .31
Cl2
 1.5 1.5 x
24.31+
2(35.45)
=95.21
1
 1.5
1.5 x 70.9
= 106.35
36.5

1

24.31
2(35.45)
=70.9
Problem 3 on Stoichiomtry WS
Final answers are:
142.82 g of MgCl2
36.5 g of Mg
106.35 g of Cl2
4/1/2015
Problem 4
Chlorine reacts with sodium
bromide to produce sodium
chloride and bromine.
sodium chloride is
Chlorine is
Na1+ and Cl-1
Cl2
NaCl
Sodium Bromide is
Bromine is
Na1+ and Br-1
Br2
NaBr
Cl2 + NaBr  NaCl + Br2
4/1/2015
Balanced?
No
Cl2 + 2NaBr  2NaCl + Br2
Problem 4 on Stoichiomtry WS
Cl2 + 2NaBr  2NaCl + Br2
Cl2
Moles
(mol)
14 .18
70 .9
Mass
(g)
 Mass
Molar
(g/mpl)
4/1/2015
NaBr
 .2 .2 
14.18

2(35.45)
=70.9
2
1
14.18 g of Cl2
NaCl
 .4 .2 
2
1
Br2
 .4 .2 
.4 x 102.9 .4 x 58.44
= 41.16
= 23.38


22.99+
79.91+
=102.9
22.99+
35.45
=58.44
1
1
 .2
.2 x 159.82
= 31.96
2(79.91)+
=159.82
Problem 4 on Stoichiomtry WS
Final answers are:
14.18 g of Cl2
41.16 g of NaBr
23.38 g of NaCl
31.96 g of Br2
4/1/2015
Problems 5 & 6
Have a part a and part b
This means there should be 2 different tables for each
question. 4 Tables in total.
4/1/2015
Start Problem 5
Now to predict the products.
Ammonium sulfate reacts with This is going to be a double
replacement reaction
sodium bromide
Ammonium Sulfate is
(NH4)2S + NaBr  ?
NH41+ SO42(NH4)2SO4
NH41+ Br1- + Na1+ S2-
Sodium bromide is
NH4Br
+ Na2S
Na1+ NO31NaNO3
(NH4)2SO4 + NaNO3  NH4Br + Na2S
Balanced?
4/1/2015
No
(NH4)2SO4 + 2NaNO3  2NH4Br + Na2S
Start Problem 6
Now to predict the products.
Aluminum chloride reacts with This is going to be a double
replacement reaction
lead (II) nitrate
Aluminum chloride is
AlCl3 + Pb(NO3)2  ?
Al3+ Cl1AlCl3
Al3+ NO3- + Pb2+ Cl1-
lead (II) nitrate is
Al(NO3)3 + PbCl2
Pb2+ NO3Pb(NO3)2
AlCl3 + Pb(NO3)2  Al(NO3)3 + PbCl2
Balanced?
4/1/2015
No
2AlCl3 + 3Pb(NO3)2  2Al(NO3)3 + 3PbCl2
Homework
Complete problems 5+6 from the Stoichometry
worksheet in your comp notebook for a
notebook stamp
You must include the 4 tables and correct
numbers for credit
4/1/2015
http://teachers.yourhomework.com/blowe/
14
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